If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9^2x-3/3^x+3=1
We move all terms to the left:
9^2x-3/3^x+3-(1)=0
Domain of the equation: 3^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
9^2x-3/3^x+2=0
We multiply all the terms by the denominator
9^2x*3^x+2*3^x-3=0
Wy multiply elements
27x^3+6x-3=0
We do not support expression: x^3
| -19-5m=-2(6-3m)+4 | | x-8=-16+3x | | 92=5v+17 | | 4(x+9)^2+29(x+9)-63=0 | | -4x+3-2x=51 | | 14x-27=59 | | 2x−40=20 | | 170=18-v | | 2(x−40)=20 | | 4(4x+2)=5x-17 | | 2r−40=20 | | 2x^2-12x+23=-23 | | 3-7x+x=15 | | 2(r−40)=20 | | 2x^2-12x+23=-é | | 2x+6=24+5x | | 26=5y-14 | | 12(4x-8)=8x-16 | | 8+2(3x-1)=x-3(3(x-14) | | 10=4n+2 | | 5(2x+4)=10(6x–8) | | 30=-x+3x+10 | | -8t^2+48t+1728=0 | | 10−2u=6 | | 2x^2-12x+46=0 | | 9^2x-3/3^x3=1 | | 135=-5(3+5n) | | 6=-4w+2(w-7) | | 3(x^2)+1=9x+1 | | 4=v/9+11 | | 6x+2=7x+5 | | x/2-4=2x+5 |